What is the relative percent difference when two simultaneous radon measurements return 8.1 and 8.4 pCi/L?

What is the relative percent difference when two simultaneous radon measurements return 8.1 and 8.4 pCi/L?

• A. 1.2%
• B. 3.6%
• C. 5.5%
• D. 7.4%

Answer: (B)

The relative percent difference is a measure of the variability between two values and is calculated using the formula: \[ \text{Relative Percent Difference} = \frac{|\text{Value}_1 - \text{Value}_2|}{\text{Average of the two values}} \times 100 \] For the given radon measurements of 8.1 and 8.4 pCi/L, the first step is to determine the absolute difference: \[ |\text{Value}_1 - \text{Value}_2| = |8.1 - 8.4| = 0.3 \, \text{pCi/L} \] Next, we need to find the average of these two measurements: \[ \text{Average} = \frac{(8.1 + 8.4)}{2} = \frac{16.5}{2} = 8.25 \, \text{pCi/L} \] Now, we can substitute these values into the relative percent difference formula: \[ \text{Relative Percent Difference} = \frac{0.3}{8.25} \times 100 \approx 3.636% \] Rounding

The relative percent difference is a measure of the variability between two values and is calculated using the formula:

[

\text{Relative Percent Difference} = \frac{|\text{Value}_1 - \text{Value}_2|}{\text{Average of the two values}} \times 100

]

For the given radon measurements of 8.1 and 8.4 pCi/L, the first step is to determine the absolute difference:

[

|\text{Value}_1 - \text{Value}_2| = |8.1 - 8.4| = 0.3 , \text{pCi/L}

]

Next, we need to find the average of these two measurements:

[

\text{Average} = \frac{(8.1 + 8.4)}{2} = \frac{16.5}{2} = 8.25 , \text{pCi/L}

]

Now, we can substitute these values into the relative percent difference formula:

[

\text{Relative Percent Difference} = \frac{0.3}{8.25} \times 100 \approx 3.636%

]

Rounding